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I dont think so, as it would be part of the Unit 6 (part a i mean) but part b can be eitherok i wanna ask u q(11) is it necessary 4 us?
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I dont think so, as it would be part of the Unit 6 (part a i mean) but part b can be eitherok i wanna ask u q(11) is it necessary 4 us?
ya ok i ned help also 4 q(12)last part and q(14) whn they ask abt verification tht rope won't slack and sry againI dont think so, as it would be part of the Unit 6 (part a i mean) but part b can be either
Sure no problem n dont apologize please Its practice for me tooya ok i ned help also 4 q(12)last part and q(14) whn they ask abt verification tht rope won't slack and sry again
ya sure and btw u wil revise it frm the book or revision guide?Sure no problem n dont apologize please Its practice for me too
Just give me a while, m still revising the chapter
The revision guideya sure and btw u wil revise it frm the book or revision guide?
actually i did it by taking time as 0 when max velocity is v=Ax(angular velocity)do ths and checkThe revision guide
btw for Q4 ii, I checked the mark scheme, and the formula they r using is new to me
But u can do it using Gradient of the steep straight part
ohh.. but how is the v maz at t=0? :S Souldnt v be 0 at that point? :Sactually i did it by taking time as 0 when max velocity is v=Ax(angular velocity)do ths and check
v is max whn it is in the equilibrium position so i guess its zero time and displacement is also zero and its the same formula for velocity bt cuz (A x angular velocity x sin x angular velocity x time is zero so A x angular velocity is left)ohh.. but how is the v maz at t=0? :S Souldnt v be 0 at that point? :S
and which formula is this? Never seen it before!
i still dont get it, at t=0 the velocity is max according to the graph right? :S so the gradient at that point (that is the velocity) will be 0 isnt it? :S isnt v max when h =0? :Sv is max whn it is in the equilibrium position so i guess its zero time and displacement is also zero and its the same formula for velocity bt cuz (A x angular velocity x sin x angular velocity x time is zero so A x angular velocity is left)
ya i kno tht whn they say max velocity it means displacement is zero hence also time wil be zero at equilibrium position ths wat i kno i don kno if its correcti still dont get it, at t=0 the velocity is max according to the graph right? :S so the gradient at that point (that is the velocity) will be 0 isnt it? :S
ohhh den i used this formula too
ohhh sry t wil nt be zero according 2 the graph i wil do the que againv is max whn it is in the equilibrium position so i guess its zero time and displacement is also zero and its the same formula for velocity bt cuz (A x angular velocity x sin x angular velocity x time is zero so A x angular velocity is left)
i'm confused y ur saying dat t=0 when when displacement is 0, if u see this particular graph, i think its at 0.32sya i kno tht whn they say max velocity it means displacement is zero hence also time wil be zero at equilibrium position ths wat i kno i don kno if its correct
No problem But i'm not getting the answer :S I'll try again...ohhh sry t wil nt be zero according 2 the graph i wil do the que again
still i didn study astrophysics i didn finish anythng til nwim affraid if time won't fit meNo problem But i'm not getting the answer :S I'll try again...
SAME HEREEEEEEEEEEEEEEEE I have to do bio as well and i just started physics -____-"still i didn study astrophysics i didn finish anythng til nwim affraid if time won't fit me
ya sure inshallaSAME HEREEEEEEEEEEEEEEEE I have to do bio as well and i just started physics -____-"
BUT we'll manage SOMEhow Inshallah dw
just 1 more last que in june 10 last part of the last queSAME HEREEEEEEEEEEEEEEEE I have to do bio as well and i just started physics -____-"
BUT we'll manage SOMEhow Inshallah dw
Keep em comming no problem n just 1 sec, i'll check dat...just 1 more last que in june 10 last part of the last que
Can u please the paper cuz i dont have itjust 1 more last que in june 10 last part of the last que
last part of last que and 4 que (4) i got stuck in amplitudeKeep em comming no problem n just 1 sec, i'll check dat...
did u get the answer for 4? I did the rest of that question, what did u want me to explain again?
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