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Statistics S1 post your doubts here

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why do you wanna do that o_O
No it can't be
you have 4 china and 6 plastic
you can't even find them all separated
Plastic China Plastic china plastic china plastic China plastic
now where will the last plastic cup go?
so no
even if you had a question which you could do that why would you wanna do that?
Was just thinking if it was possible for this type of question to appear?
Thanks for clarifying!
 
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for the actual question
_P_P_P_P_P_P_
there are 7 places so 3 china mug can arrange in 7p3
final answer 7P3*6!

For your question
_C_C_C_
there are only 4 places. 9 plastic mugs cannot be arranged in 3 places 4P9 (you can't do that)
Well, actually these 9 can be placed in multiple ways in these 4 places as more than one can be placed at one place but this is actually not in our syllabus.
 
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i) No orange mean 200 left
probability of the first disc being NOT orange =200/300 AND probability of the second disc not orange= 200/300 ..... it keeps going like this
so basically (2/3)^5
ii) if you count the number which end with a 6 there are a total of 30 in 300
p=(30/300)=0.1
Exactly 2 discs use binomial after this to get P(X=2)
n=5 p=0.1 q=0.9 r=2
iii) 10 discs which are both orange and ending with a 6
p=(1/30)
again use binomial
iv) mean=np
varince=npq
n=5
p=100/300=1/3
and q=2/3
 
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o/n/12/63
Q6 part c pleaseeeeee! my exam is tomorrow
The probability of placing each one of the coloured tile (Let's take an example of black) is 1/3.. right? The second tile must not be black, therefore: P(Not black) = 1 - 1/3 = 2/3.
The first tile could be any one of the three tiles, so the probability is 1 (Just for the first tile). The next seven tiles have the probability of 2/3.

Hence, the total probability becomes.. 1 * (2/3)^7 => 0.0585
 
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