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sorry but i havent checked through marking scheme , if you found some thing wrong in it pls correct me. !!!
I think u have to take half the are of cylinder which u did then take quarter the area of a sphere and also add half the area of the circle add these up and u get the surface area
Its only released when syllabus or paper format is changed this year it wasnt
,
Have u checked ur answer with the ms because i think theres something fishy in it
do you know the answer ??
actually the answer not the solution!
I could not understand i have took the area of 1/4 sphere and 1/2cylinder , but havent took area of circle bcuz that circle is already included in cylinder!!!
Actually no its not unless u take the full formula that is 2(pi)rh + 2(pi)r^2
now here 2(pi)rh means the area of the curved surface of the cylinder and not the circle while the circle formula u use gives the area of circle in this way u get the area of whole figure !
Now the formula doesnt mean that u cant play with it u can remove 2 from the area of circle when u only require one circle and divide multiply according to ur need !
Oh yes i do know it and i told how to get the correct answer
ok then how do you get the surface area of the liquid in the sphere...
i got all the rest i got stuck on that part...:/
when does it ask abt that part,now can u tell me are u talking abt the same question then tell me the part ??
u r welcome!Now I get it thanks...my doubt is cleared
i want to ask a little question in part b in second part how is d2 2 ... d1=(6-2)=4....wont d2 be (12-6)??...b) i)
There are different ways of doing this... You can use the formula if you wish...
a + (n-1)d
a is the first term...
d is difference...
So 10+(n-1)4
10+4n-4
6+4n
OR
find the difference between the values...
4 in this case...
Then write it as 4n+-(x) = 10
10 is the first value... S0 n =1
4(1)+-(x)=10
You have to find such x value which satisfies the equation... So it it is 4 in this case... Put it in the first equation and just take the left side of it... 4n+6
ii) The first difference is not the same for this part... The second difference is...
So its a quadratic sequence..
The formula for quadratic sequence is a+(n-1)d1+(1/2)(n-1)(n-2)d2
a is the first term of sequence
d1 1st difference
d2 2nd difference...
a is 2
d1 is 4
d2 is 2
2+(n-1)4+(1/2)(n-1)(n-2)2
Solve and you get n^2+n
c) Add the equations of b) i and b) ii
n^2+n +4n + 6
n^2+5n+6
n^2+2n+3n+6
n(n+2)+3(n+2)
(n+3)(n+2)
(n+2)(n+3)
2, 6, 12i want to ask a little question in part b in second part how is d2 2 ... d1=(6-2)=4....wont d2 be (12-6)??...
for x axis invariant line is y=0In O level matrix transformation what is the invariant line for shear parallel to both
x axis.....
y axis....
ohh thnku so much for ur help bro....will this formula be applied to any sequence where the difference is different?? (a+(n-1)d1.+1/2(n-1)(n-2)d2)2, 6, 12
First difference between the consecutive numbers : 4, 6
Second difference between the new numbers is now 6-4= 2.
Thank you !for x axis invariant line is y=0
for y axis invariant line is x=o
I think so...ohh thnku so much for ur help bro....will this formula be applied to any sequence where the difference is different?? (a+(n-1)d1.+1/2(n-1)(n-2)d2)
Cricle has five sectors with the same angle...http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w11_qp_22.pdf
guys need some serious help in question 3 a) ii) here!!!
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