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Physics: Post your doubts here!

Albert Einstein

Albert Einstein

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bamteck said:
And for the (a)(ii) ?
Click to expand...

See ranging from 20 to 40 difference is 40 degree then frm 40 to 60 is 70 degree...frm 60 to 80 is 90 degree .....what u observ is the difference between the angle isis approximately 2/3 . e.g(70-40=30) and 90-70=20 (2/3 of 30) then 102-90=12 (approximatel 2/3 of 20) therfore whn v= 100 x 10^-3(1.0x10^-5)... the increment is 2/3 of 12 = 8..hence postion for 1.0 x 10^-3 is equal to 102 + 8= 110 degree..refer to markscheme the ans is between 107 and 113 so any doubt in the ans ??
 
bamteck

bamteck

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Albert Einstein said:
See ranging from 20 to 40 difference is 40 degree then frm 40 to 60 is 70 degree...frm 60 to 80 is 90 degree .....what u observ is the difference between the angle isis approximately 2/3 . e.g(70-40=30) and 90-70=20 (2/3 of 30) then 102-90=12 (approximatel 2/3 of 20) therfore whn v= 100 x 10^-3(1.0x10^-5)... the increment is 2/3 of 12 = 8..hence postion for 1.0 x 10^-3 is equal to 102 + 8= 110 degree..refer to markscheme the ans is between 107 and 113 so any doubt in the ans ??
Click to expand...
Thank you very much ! You are a genius !
 
Jigar

Jigar

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A Car X is travelling at a steady speed of 15 m/s. It overtakes Car Y which is travelling at 10 m/s. The driver gets irritated and immediately starts to accelerate uniformly. Car Y catches up with Car X after 20sec. Draw a velocity time graph for the two cars and determine the speed of Car Y when it catches up with Car X.

Please attach the graph if possible....and please provide a explanation to your answer......

Thanks in advance....................
 
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